chemistry question please help mememem?

Question

How many grams of sulfur (S8) would have to be dissolved in 145.0 g of carbon tetrachloride to lower the freezing point by 2.10 degrees celsius?


kf = 29.8 K-kg/mol for CCl4

Answer 1

I guess you can use my question as a ref.

How many grams of sulfur (S8) would have to be dissolved in 110.0 g of carbon tetrachloride to lower the freezing point by 1.70 degrees celsius?

kf = 29.8 K-kg/mol for CCl4

Enter a numerical answer only, do not include units in the answer you enter

Correct, computer gets: 1.60945503355705

Hint: Don't forget to include the van't Hoff factor i, if it is needed.
Top

This is how I solve it:

(1.70)*(0.110)/(1)(29.8)=.0062751678

(32.066)*(8 atoms)*(.0062751678)=1.609756245

Answer 2

the formula is delta T = Kf m (where m is molality)

You have the Kf and the delta T. Solve for the molality

But the molality is moles per Kg. of CCl4. You have 145 grams of CCl4

So set up a ratio and you will get moles of S8 required for the 145 gr. Now convert the moles of S8 to grams and you are done