If my graph had solutions of
(9,30) and (12,40), what
would the answer to this
question be: The solutions you found are the y intercept and x intercept on the graph. Explain why these names are appropriate.
2007-03-07 13:42:58 · 6 answers · asked by colada15 3 in Education & Reference ➔ Homework Help
The problem was 9x + 12y = 360
2007-03-07 13:53:27 · update #1
Something's wrong with your graph. The X and Y intercepts are where your line crosses X=0 and Y=0. Could you show the problem? That could help people tell you what's up. Good luck!
2007-03-07 13:48:03 · answer #1 · answered by just wondering 3 · 0⤊ 0⤋
To be the y-intercept, x has to be 0 like (0, #).
To be the x-intercept, y has to be 0 like (#, 0).
This is where the lines of whatever you're graphing cross the x and y axes
2007-03-07 13:47:21 · answer #2 · answered by SnowFlower 2 · 1⤊ 0⤋
No, those points are not intercepts. The x-intercept is on the x-axis and so would have 0 for its y-coordinate, and the y-intercept similarly would have 0 for its x-coordinate.
2007-03-07 13:47:34 · answer #3 · answered by hayharbr 7 · 0⤊ 0⤋
Your solutions are wrong. The y-intercept should be (0,y) and the x-intercept should be (x,0).
2007-03-07 13:46:25 · answer #4 · answered by Paul B 2 · 0⤊ 0⤋
i might say which you have been outstanding yet whilst the guy correcting your attempt had to be an *** i assume they could mark it incorrect. extremely the intercepts are (5,0) and (0,10) yet that could advise that X=5 and Y=10 so i say you will get the credit.
2016-10-17 12:56:08 · answer #5 · answered by Anonymous · 0⤊ 0⤋
I thought you just did 40-30 over 12 - 9 and solved...but then again I suck at these types of problems...I wish I could be of more help...sorry! :-D
2007-03-07 13:52:31 · answer #6 · answered by lildevilgurl152004 7 · 0⤊ 0⤋