So let's say we have a step up transformer. It is going to increase the voltage and energy is conserved therefore current will decrease in wire. But what I dont get is, how is that going to save the power loss?? Power = I^2 *R so if current decreases in the wires power loss also decreases. OK. But Power also equals V^2/R so when V increases power loss increases?? I am so confused!!!
2007-03-07 13:30:10 · 2 answers · asked by Just livin my life 2 in Science & Mathematics ➔ Physics
What in the world? I wanna know who comes up with this stuff, I don't like math i'm soo bad at it,lol.
2007-03-07 13:38:30 · answer #1 · answered by hev_1985 4 · 0⤊ 1⤋
Power loss is a result of square of the current and the resistance. Given by the formula I^2(R)=P, this means if the current is doubled the power loss will be four times greater.
Since the power transmitted is equal to the product of the current, the voltage and the cosine of the phase difference φ (P = IVcosφ), the same amount of power can be transmitted with a lower current by increasing the voltage.
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I think, the size of the wire is to allow current to travel.
The insulation around the wire is because of the voltage. If we increase the voltage we increase the insulation and decrease our loss.
2007-03-07 15:00:52 · answer #2 · answered by Anonymous · 0⤊ 0⤋