Period of leg?

Question

The period of the leg can be approximated by treating the leg as a physical pendulum, with a period of 2pi*sq rt(I / mgh), where I is the moment of inertia, m is the mass, and h is the distance from the pivot point to the center of mass. The leg can be considered to be a right cylinder of constant density. For a man, the leg constitutes 16 \% of his total mass and 48 \% of his total height.

Find the period of the leg of a man who is 1.81 m in height with a mass of 75 kg. The moment of inertia of a cylinder rotating about a perpendicular axis at one end is m*(l^2) / 3

Answer 1

I would say that a period
T=2pi*sq rt(I /g)

l= length from a pivot point to the center of the mass
l= .48 x 1.81 =0.869 m

Moment of inertial does not play much of role here.

finaly
T=2pi*sq rt(I /g) =
T=2 x 3.14159 x sqrt(0.869 m/9.81)=1.87 sec