calculating molarity by mass?

how many grams of KI are needed to prepare 100. mL of 0.55M solution?

2007-03-07 12:50:27 · 1 answers · asked by moody 1 in Science & Mathematics ➔ Chemistry

find the mole of solution
100mL*(1L/1000mL)*(.55mole/1L) =.055 mole
.055mole*166.0g/1mole=9.13g
(KI=166g/mol from periodic table)
good luck

2007-03-07 12:57:31 · answer #1 · answered by Helper 6 · 0⤊ 0⤋

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