Superwoman is hovering above the ground when a person free-falling goes by her at a terminal velocity of 140 km/h. Unfortunately, the parachute does not open. Fortunately, Superwoman is around. If it takes her 1.9 s to realize the person is in distress, what must her acceleration be if she is to catch the parachutist just before she hits the ground 1000 m below?
2007-03-07 11:56:44 · 3 answers · asked by Chess 2 in Science & Mathematics ➔ Physics
First convert km/h into m/s.
Next find the time it will take the parachutist to hit the ground. Since she is a terminal speed, this means her speed is constant so finding the time is easy,
use y=v t
Once you have the time, subtract 1.9 s (a very slow reaction time for superwoman, she must be distracted) to get the time superwoman has to accelerate.
Now use the equation
y=½ a t²
You have the distance and the time, just solve for the acceleration and you are set.
2007-03-07 12:08:05 · answer #1 · answered by 2 meter man 3 · 1⤊ 0⤋
5
2007-03-07 20:24:19 · answer #2 · answered by the DIRKSTER 2 · 0⤊ 0⤋
you must find the time it takes for the person to hit the ground.
which comes out to 25.714 seconds. but shes a woman, so her reaction time is a rediculously slow 1.9 seconds. She has only 23.8143 seconds. Distance = 1/2at^2. 1000m = .5 * a * 23.8143^2. thus a = 3.527 m/sec^2
2007-03-07 20:39:37 · answer #3 · answered by thereytrain 2 · 0⤊ 0⤋