hi please help, dynamics, have the answer, need help doing it?

Question

a woman of mass 65kg is trying to rescue a man of mass 80kg who has fallen over the cliff's edge. The woman is standing on a horizontal frictionless surface 15 metres from the edge of the cliff. dtermine how long it will take before the woman reaches the edge of the cliff, starting from rest
the answer is 2.4 seconds

thanks!!

Answer 1

Calin C made 2 errors that seem, I guess coincidentally, to give the right answer.

Using Calin C's variable names, the man's weight is M*g. That force accelerates the both of them.
M*g = (M+m)a
So
a = M*g/(M+m)

The time is given by
d = a*t^2/2
So
t^2 = 2*d/a = 2*d*(M+m)/M*g

Answer 2

mass of woman=m
mass of man=M

The force the woman is pulled is: Mg. Her force of inertia is: ma
a=Mg/m
A body moves a distance d, from a full stop, under an acceleration a: d=at/2, therfore, t=2d/a, or in our case, t = 2dm/MG. I am pretty sure that will give you the answer you have... Success