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at standard atmosphere pressure, temp. 85 degrees F, and air inside of large balloon is heated to 150 degrees F . how much weight will this large balloon be able to life if it is a sphere w/ radius of 25 meters? show WORK i couldnt figure it out thank you

2007-03-07 09:53:35 · 2 answers · asked by blackbeltcc4 2 in Science & Mathematics Physics

2 answers

Weight the balloon can lift is based on the difference generated by a buoyant force of hot in cold air.
w=(m2-m1) g

m2= p2V
m1=p1V

w= (p2- p1)V g
assuming dew point 20 C and pressure 1 atm or 1013 mb
p2- density of cold air at 85 F (29.4 C)= 1.1562 kg/m^3
p2- density of cold air at 150 F (65.6 C)= 1.0327 kg/m^3

w= (p2- p1)V g
V=4/3 pi r^2

w=(1.1562 - 1.0327) x 4/3 x pi x (25)^2 x 9.81w =3170 N
or
m=w/g=323 kg

have fun!

2007-03-08 07:21:22 · answer #1 · answered by Edward 7 · 1 0

utilizing v = u + at the position u is initial % and v very last % all of us understand that in both circumstances v = 0 because both autos come to relax. initial % u: u + (-4.2)t1 = 0 or u = 4.2t1 initial % 2u : utilizing same theory 2u = 4.2t2 Dividing 2d equation by technique of first 2u / u = 4.2t2 / 4.2t1 t2 / t1 = 2 t2 = 2 t1 This shows the 2d vehicle takes two times the time to stop. u1 = 16 m/s so t1 = 16 / 4.2 = 3.80 one s u2 = 32 m/s so t2 = 32 / 4.2 = 7.sixty 2 s

2016-12-05 09:27:47 · answer #2 · answered by miracle 4 · 0 0

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