The value of g at the Earth's surface is about 9.8 m/s2. What is the value of g at a distance of twice the Ear

Question

The value of g at the Earth's surface is about 9.8 m/s2. What is the value of g at a distance of twice the Earth's radius?

Answer 1

Gravitation decreases with the square of the distance. Therefore, if you double the distance, the gravitation will decrease four time. Result: 9.8/4=2.95 m/s2

Answer 2

Force of Gravity - and, therefore, Acceleration of Grvity -vary inversely as the square of the distance. At the surface we are about 12,500 miles from the center of the gravitational mass. Double the distance and have a quarter the force and an accelerstion of gravity of 2.45 m/s.

Answer 3

Here is an interesting answer for consideration while moving in the opposite direction you requested. When at a distance of 0.716 miles from the center of our planet, were a mass able to be released in that location, it would exceed the speed of light in one second. In that this is a physical impossibility (mass is unable to exceed the speed of light) what happens to all the mass within that radius? In our sun the distance is 400 miles from its center when mass begins exceeding the speed of light.

http://360.yahoo.com/noddarc there is a short writing "The Problem and Repair of Relativity" that may be of interest to you.