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If you have 85 liters of argon gas at 164 Celsius, and the pressure is 687 torr, how many moles of argon are there?

i don't really get this question, I appriciate any help, thanks

2007-03-07 09:34:33 · 2 answers · asked by starttoday 3 in Science & Mathematics Chemistry

2 answers

PV = nRT

(687torr)(85L) = n(62.3 L-torr/mol-deg)(437K)

n = (687)(85)/(62.3)(437) = 2.1 moles Ar.

2007-03-07 09:46:32 · answer #1 · answered by steve_geo1 7 · 0 0

Use PV = n RT and solve for n.

n =PV/(RT) where n= # moles, P is pressure in atm, T is temp Kelvin, R = 0.0821, V must be in liters

Now, 687 torr = 687/760 atm = 0.904 atm

So n = (.904)(85)/(.0821 * 437). You do the arithmetic. Okay?

2007-03-07 09:41:07 · answer #2 · answered by Anonymous · 0 0

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