How many g of zinc metal will react with 24.5 Ml of 2.0 moles hydrochloric acid (HCl), forming zinc chloride?
How do you do this? Im totally lost.
2007-03-07 09:27:57 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The equation is:
Zn (s) + 2 HCl (aq) --> ZnCl2 (aq) + H2 (g)
It takes 2 moles of HCl to react with 1 mole of Zn
2.0 M HCl is 2 moles per Liter of solution. The number of moles in 24.5 mL is:
2.0 mole/Liter * 24.5 mL/1000 mL/L = 0.049 moles HCl
The mass of Zn metal consumed is:
0.049/2 moles * 65.41 g/mole = 1.60 grams
2007-03-07 10:26:06 · answer #1 · answered by Richard 7 · 9⤊ 0⤋
this is what i THINK. i'm not 100% but,
1st set up the equation:
Zn+HCl yields ZnCl + H
2nd set up a t-chart
24.5ml on top 2.0 moles at the bottom then draw a line then 1mole on the top beside the line drawn betweeb 24.5 ml and below that 6.02 *10 to the 23rd. then cross out the mole units and multiply the top numbers together (24.5 * 1) and then 6.02 *10 to the 23rd * 2.0) then divide those answers by each other.
. ...i think that's what you're talking about. if not then...sorry!
2007-03-07 17:45:10 · answer #2 · answered by erica h 2 · 0⤊ 0⤋