what is the magnitude of the upward componet of the force ascting on the stake?

Question

Beth, a construction worker, attempts to pull
a stake out of the ground by pulling on a rope
that is attached to the stake. The rope makes
an angle of 41.3degree with the horizontal.
If Beth exerts a force of 164.4 N on the
rope, what is the magnitude of the upward
component of the force acting on the stake?
Answer in units of N.

Answer 1

Use a bit of trig to separate the vertical and horizontal components of the rope tension:

the horizontal is cos(41.3)

and the vertical is sin(41.3)

So the upward force is
sin(41.3)*164.4

j

Answer 2

for the magazine, use the pathag. theorem(hi, that rhymes!) c = squarert(40^2 + 30^2) = 50 N for the dircetion, use trig... tan(theta) = opp/adj implies theta = tan(-a million)(opp/adj) theta = tan(-a million)(40/30) = fifty 3.13 levels very final answer...50 N @ fifty 3.13 levels with appreciate to the horizontal tension