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I cant figure between two answers

Long wavelength visible light
a. has a higher frequency than short wavelength visible light
b. will appear red in color to the average human eye

2007-03-07 07:18:59 · 4 answers · asked by Anonymous in Science & Mathematics Astronomy & Space

4 answers

B

2007-03-07 07:21:22 · answer #1 · answered by BILL@CA 5 · 0 0

Yes, B is correct... I'll attempt to explain why.

The light waves you can see in the visible spectrum range from Red at the long wavelength end to Violet at the short wavelength end . You can remember the colors in the rainbow by the anagram Roy G. Biv for red orange yellow green blue indigo violet. The longer the wavelength, the more shifted to the red.

A is wrong because a long wavelength = low frequency since less wave fronts will pas a point in a given amount ot time. So A is basically trying to say that a long wave length is shorter than a short wavelength. That answer just doesn't compute. So B it is.

2007-03-07 07:35:52 · answer #2 · answered by CurazyJ 2 · 0 0

velocity of a wave = wavelength * frequency. Assuming constant velocity, say of the speed of light equal to 300 000 000 meters/second, with wavelength having units meters, and frequency having units per second, then answer a. cannot be true. Also, think about the visible light spectra, colors ROYGBIV (red, orange, yellow, green, blue, indigo, and violet). You (probably) already know that ultraviolet light from the sun is not visible to humans. "Ultra" in this sense means "greater in magnitude of energy", I believe. This would lead me to believe that ultraviolet would be just beyond the violet end of the spectra, and in fact, it is. On the other end of visible light is red wavelength, and just beyond red is infrared, etc. All this to say, long wavelength (meters) has a lower frequency (per second), and thus, appears red in color.

2007-03-07 07:33:07 · answer #3 · answered by go tigers 1 · 0 0

B is correct

2007-03-07 07:22:09 · answer #4 · answered by Anonymous · 0 0

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