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A helicopter lifts a 69 kg astronaut 11 m vertically from the ocean by means of a cable. The acceleration of the astronaut is g/10.
a) How much work is done on the astronaut by the force from the helicopter?
(b) How much work is done on the astronaut by her weight?

2007-03-07 05:43:26 · 2 answers · asked by Rogue Bagel 2 in Science & Mathematics Physics

2 answers

Work is force applied through a distance. The forces acting on the astronaut are gravity (mg) plus the .1g of acceleration from the helicopter. So, the work is going to be 1.1g x mass of the astronaut x 11m

2007-03-07 05:59:29 · answer #1 · answered by nyquist1995 2 · 0 0

F=ma w=Fd=mad

(69kg)(1m/s^2) (11m)

The work is the same on both cases only with different directions

2007-03-07 14:43:46 · answer #2 · answered by piri82 3 · 0 0

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