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12 mg of a certain protein was dissolved in water to make a solution of 2.00 mL at 22C. If the osmotic pressure is 1.15 torr, what is the molecular mass of the protein?

2007-03-07 05:33:46 · 2 answers · asked by Gemini 2 in Science & Mathematics Chemistry

2 answers

concentration in liter ing 0.012/0.002=6g/l = 6kg/m^3
1.15 torr=133*1.15=153pa
T = 22+273=295+K

OP = RT*c/M

M = RTc/OP= 8.31*295*6/153 =96.100kg =96100g

2007-03-07 05:56:25 · answer #1 · answered by maussy 7 · 0 0

I guess you can use my question as a ref.


22 mg of a certain protein was dissolved in water to make a solution of 4.50 mL at 26C. If the osmotic pressure is 1.25 torr, what is the molecular mass of the protein?

To enter an answer in scientific notation use an e




6.022 x 1023 = 6.022e23



1.340 x 10-8 = 1.340e-8


Enter a numeric answer only, do not enter units.

Correct, computer gets: 72931.7185422222

This is how I solved it:

(0.022)*(0.082)*(273+26)/((1.25/760)*0.0045)=72931.7185422222

2007-03-08 22:01:45 · answer #2 · answered by Raki 3 · 0 0

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