A transformer with 16000 turns in the primary and 1000 turns in the secondary?

Question

has an output of 32.0 A at 120 VAC. Find the input voltage and current, assuming 95% effiecientcy

Answer 1

n1=Primary turns=16000.
n2=secondary turns=1000.

v2=output voltage = 120 V

n2/n1 = v2/v1
1000/16000 = 120/v1
v1 = 16000*120 /1000 = 1920

this number is achieved after the impact of efficency so :
1920 =95/100 real V1
so real V1 = 1920*100/95 =2021.05 V


for the current it is the same just the formula is :
I2 / I1 = n1/n2
16000/1000=32/ I1
I1= 2

but , the real I1 is :
2= 95/100 real I1
real I1 = 200/95 =2.105 A

Answer 2

Look, to tell you the truth, I have never studied that topic, I mean, I have never made a transformers exercise, but this one, is kind of easy, I have a book ( Sears - Zemansky ), and I found :

V2 / V1 = N2 / N1

N = turns

V = potential difference

Then, in your problem :

1000 / 16000 = 120 / V1

V1 = 1920

95%*1920 = 1824 Volts

and :

V1*I1 = V2*I2

I1 = input current

I2 = output current

1824*I1 = 120*32

I1 = 2.1 Amperes

Hope that might help you