consider the statement: if n is an integer and n^k is odd for some?

Question

k belonging to Z>0 then n is odd
i. write the converse statement
ii. is the converse statement true? either prove or provide a counter-example
thanx:)

Answer 1

"If n is an integer and n^k is odd for some k belonging to Z > 0, then n is odd."

(i) The converse of the statement is,

If n is odd, then n is an integer and n^k is odd for some k belonging to Z > 0.