Question: A 2700 ohm resistor and a 1.1 x 10^-6 F capacitor are connected in a series across a generator (60.0 Hz, 120 V). Determine the power delivered to the circuit.
My Approach: I found the reactance capacitance and got 2409 ohms. Then I plugged numbers into V = IZ to get current. Notably, I divided 120 V by square root of 2 (for peak value purposes). My answer for current was I = 2.35 x 10^-2 A. Then, I plugged the current in the P = IV cos (0) and got P = 2.8 W. Are my numbers correct? My main question comes when I divided voltage by square root of 2. Appreciate all the help I can get!
2007-03-07 04:41:12 · 2 answers · asked by Jimmy 3 in Science & Mathematics ➔ Physics
120 volts is the RMS value so you don't need to divide. Don't forget to take into account the phase difference between the voltage and current and keep in mind that only the resistor dissipates power. I don't believe your phase angle of 0 is correct. That only works for a resistive load.
2007-03-07 04:54:20 · answer #1 · answered by Gene 7 · 0⤊ 0⤋
(2700 - 2652.58i) is your impedance.
2007-03-09 01:35:59 · answer #2 · answered by joshnya68 4 · 1⤊ 0⤋