8x -4y = 16
y = 2x -4
2007-03-07 04:24:57 · 5 answers · asked by Michelle P 1 in Science & Mathematics ➔ Mathematics
8x - 4y = 16
y = 2x - 4
First, divide the first equation by 4.
2x - y = 4
y = 2x - 4
Now, plug in y = 2x - 4 into the first equation.
2x - (2x - 4) = 4
Solve
2x - 2x + 4 = 4
4 = 4, which is a true statement. This means x is equal to any real number (let's call it s).
Therefore, the solution set is
x = s, y = 2s - 4 for all real number s.
2007-03-07 04:30:49 · answer #1 · answered by Puggy 7 · 0⤊ 0⤋
on account which you be attentive to that y=2x-4 then you could plug that in the time of for y in the different equation 8x-4(2x-4)=sixteen 8x-8x+sixteen=sixteen meaning x=0 y=2(0)-4 y=-4 which tests out once you plug the x and y values into the two equations
2016-11-23 13:21:32 · answer #2 · answered by lawver 4 · 0⤊ 0⤋
8x - 4 (2x - 4) = 16
8x - 8x +16 = 16
16 = 16
it's a true statement.
2007-03-07 04:30:20 · answer #3 · answered by cutie.pie_xo 3 · 0⤊ 0⤋
Strictly speaking, the equations cannot be solved since there are two variables x and y and only one equation! Both the equations are two different forms of the same identity.
2007-03-07 04:34:09 · answer #4 · answered by Swamy 7 · 0⤊ 0⤋
8x - 4(2x-4) = 16
8x - 8x + 16 = 16
16=16
2007-03-07 04:29:32 · answer #5 · answered by Anonymous · 0⤊ 0⤋