Resistance - voltage drops please help?

Question

Resistance - voltage drops please help?

I have 5 volts battery at the bottom and three resistors - 2 in series parallel to the battery (1 and 2 ohms) and one above them parallel to them (3 ohms). Please help me to calculate voltage drop accross each one.
How to I calculate current through those two lines - I know the total current and I know that the sum of those two is total. Helppppp!

Answer 1

There are 2 resistors in series across 5 V. 1 Resistor is 1 ohm in series with 2 ohm This is 1 leg. Divide 5 V by 3 for the total resistance in that leg. The resistor with 1 ohm would have 1/3 of the total,the other would have 2/3 the total voltage of 5V .That takes care of the first leg and someone is playing with u as the 2nd. leg also has 3 ohms. so the current will divide equally in leg. 1 & 2. Hope this helps.

Answer 2

seem, it somewhat is not an extremely complicated exercising, yet, you somewhat desire to make a picture, and you're growing to be to be, 2 resistors in sequence and one above in parallel with those 2 resistos, and above the three resistors, you have the battery. hint one : discover the equivalent resistor : 2 in sequence : Req = a million + 2 = 3 and working with the parallel one : a million / 3 + a million / 3 = a million / Rt Rt = 3 / 2 (ohms) Now, we can discover the finished modern-day, with the battery, permit's prepare the Ohms ' regulation : 5 = I*3/2 I = 10 / 3 (Amperes) once you have resistors in sequence the present is an identical, once you have resistors in parallel, the aptitude distinction is an identical, thus 5 volts. 5 volts, is the aptitude distinction between the three oms resistor and between the two resistors in sequence ( a million ohm and a pair of ohm ) employing 5 volts and the resistor of three ohm, we can discover it somewhat is modern-day : 5 = 3*I' I' = 5/3 amperes >>> modern-day interior the three ohm resistor. to discover the present on the different resistors ( sequence resistors ), do exactly this : entire modern-day - 5/3, why ? simply by fact, the present is shifting by using those 2 lines, so the present could be an identical, outstanding ? so : 10 / 3 - 5/3 = 5/3 amperes On each and each line, you will discover 5 / 3 amperes, and the finished modern-day would be 10 / 3 Amperes

Answer 3

to do this problem you need to calculate the amps

let i = amps
let e = volts
let r = ohms or resistance

ohm's law states that i = e/r
and e = i * r

Answer 4

You had better learn how to post a picture of a circuit if you want decent answers to questions like this.

Answer 5

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