What is the molecular mass of the protein?

Question

12 mg of a certain protein was dissolved in water to make a solution of 3.00 mL at 23C. If the osmotic pressure is 1.15 torr, what is the molecular mass of the protein?



To enter an answer in scientific notation use an e

6.022 x 1023 = 6.022e23

1.340 x 10-8 = 1.340e-8

Answer 1

well...
It looks like a standard pV=nRT question..
so here's what you do..
p=pressure (pa)
V= volume (dm^3)
n= number of moles (mol)
R= universal gas constant (J/K * mol)
T= thermodynamic temperature(that means it's in kelvins, not celsius)

so n=m/M
M= molar mass, the thing you're looking for

converting the formula gives you

n= pV/RT
using n= m/M

m/M = pV/RT

converting again:


M= RTm/ pV
the data you now just have to put in this formula are:

R = 8,314 J/Kmol
T= 296 K
m= 12mg = 12e(-3) g = 0,012 g
p= 1,15 torr (1 torr = 133,32 pa)
= 153,31 pa
V = 3ml = 3 cme3 = 3e-6 me3

after you put this into the formula given above you will get :


M= 64208,31 g/mol

Answer 2

Do your own homework. You're not asking for help, you're not asking for an explanation, you're just asking people to do your homework for you. Do your own homework.