the table shows the no. of children living in 20 houses
no. of houses = no. of children
0 = 5
1 = 6
2 = 7
3 = 2
estimate the probability that the number of children living in a randomly chosen house is at least two.
PLEASE HELP, TOMORROWS MY MATH TEST!!!
2007-03-07 02:19:44 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
This isn't too hard. Just remember the key term "at least".
I believe you have your numbers reversed, I think you meant no. of children = no. of houses.
Just sum the number of houses that have at least two children. In your chart houses with 2 and 3 children qualify. So we can conclude that 7+2=9 houses that have two or more children.
Just divide the number of houses that qualify by the total number of houses (20) and you have your probability.
In this case it is 9/20 = .45 or 45%..
2007-03-07 02:26:42 · answer #1 · answered by uahgrad05 3 · 1⤊ 0⤋
Total number of houses = 20
Total number of houses w/ >2 children = 9
9 is 45% of the total houses (20).
The Probablity means what are the chances of you randomly picking a house with 2 or more children in it. Again, 9 out of 20 or 45%
2007-03-07 10:31:46 · answer #2 · answered by Rick 3 · 1⤊ 0⤋
Probability is simply the number of successful outcomes divided by the total number of outcomes.
Total outcomes is the number of houses, which looks like 6 to me. How many houses have at least 2? Just divide that by the total to get probability.
If you mixed up the tables headings, the # of houses is actually 20 as you said. The logic still remains the same.
2007-03-07 10:24:39 · answer #3 · answered by scruffy 5 · 0⤊ 0⤋
im not sure but i think you set up a porportion . the number of kids over the amount of houses and then 2 over X then multiply to get ur fraction.
2007-03-07 10:28:13 · answer #4 · answered by tony c 3 · 0⤊ 0⤋
100%
2007-03-07 10:33:56 · answer #5 · answered by philo 2 · 0⤊ 0⤋