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If before Adsorption I had 550 cm3 of NaOH and after adsorption I had 482cm3 of NaOH?

2007-03-07 01:27:16 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

You haven't told us the molarity of NaOH but assuming it is 0.1 mol dm-3 then to find the concentration you can use the following formula:

Amt of substance in mols = volume x concentration
= 482/1000 x 0.1 (we divide vol by 1000 to convert to dm3)
= 0.0482 mols

Concentration = Vol/Mols
= 482/1000 / 0.0482
= 10 mol dm-3

You can shortcut the method but I wanted to show you the proper text book method.

Hope this helps.

2007-03-07 10:29:38 · answer #1 · answered by Anonymous · 0 0

The question isn't clear. You had 550 cm3 of NaOH soln. in water? At what concentration? Onto what was it adsorbed?

2007-03-07 09:47:17 · answer #2 · answered by Ian I 4 · 0 0

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