2007-03-07 01:08:47 · 6 answers · asked by mohan 1 in Science & Mathematics ➔ Physics
mass of train = 16000 Kg
Force of train = 35000 N
acceleration = 35000/16000
acceleration = 2.1875
2007-03-07 01:19:44 · answer #1 · answered by varun 2 · 0⤊ 0⤋
actually the question is:- A 8000kg engine pulls a train of 5 wagons, each of 2000kg, along a horizontal track.if the engine xerts a force of 40000N and the track offers a friction force of 5000N, then calculate the acceleration of the train.
ANSWER
resultant force=40000-5000
=35000N
m=2000*5
=10000kg
F=ma
a=F/m
=35000 / 10000
=3.5m/s^2
2007-03-07 01:41:14 · answer #2 · answered by honey 3 · 0⤊ 1⤋
The chains (or couplings) are of uniform length, because of the fact the formation of a convention can selection from each and every day, based upon the call for. Coal wagons may well be attatched or detatched en path, and a various coal wagon may well be formed next to the locomotive each and each time. interior the united kingdom, the locomotive employs a "locomotive screw coupling", it particularly is rather stable certainly. the the remainder of the couplings on coal wagons are common instanter couplings (on HAA wagons, besides).
2016-12-18 07:33:16 · answer #3 · answered by ? 4 · 0⤊ 0⤋
Mass of train = Engine + 5 wagons
Mass = 8000 + 10000 = 18000 kg
Force = Mass x Acceleration
Therefore-:
Acceleration = Force / Mass
Acceleration = 35000 / 18000
Acceleration of whole train = 1.94 ms^-2
All parts of a connected train accelerate with the same velocity...
2007-03-07 01:22:17 · answer #4 · answered by Doctor Q 6 · 0⤊ 1⤋
1) I would think you add up all of the mass (8000 + 5x2000) =18000 kg
2) to get the acceleration, divide the force by the mass or 35000N/18000kg = 1.94 m/s
The acceleration is the same for all parts of the train.
2007-03-07 01:16:19 · answer #5 · answered by Anonymous · 0⤊ 1⤋
my mind stopped working as sooon as i red ur question......
2007-03-07 01:12:34 · answer #6 · answered by Anonymous · 0⤊ 1⤋