find the x-intercept of a straight line equation in the form y=mx+c (or y=mx+b)
How do I find it? y=2/5x+1 (the y-intercept here is 1, gradient=2/5)
Thankyou.
2007-03-07 00:49:41 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
put y=0
therefore
0=2/5x+1
x= -5/2--x-intercept
2007-03-07 00:53:19 · answer #1 · answered by Maths Rocks 4 · 0⤊ 0⤋
In order to find the x-intercept, you have to set y=0. So you have to solve for x in the equation 0=2/5x+1
2007-03-07 08:58:14 · answer #2 · answered by Star 6 · 0⤊ 0⤋
just replace y with zero, then you will the get x intercept.
y=2/5 x + 1
replacing y with zero
0= 2/5 x +1
-1= 2/5x
-5/2 = x
Hence your x-intercept is -5/2.
To get the x-intercept of any linear equation of the form
ax + by + c =0
we replace y with 0.
So ax + 0 + c =0
Hence x = -c/a
2007-03-07 09:02:53 · answer #3 · answered by SensitiveMe 2 · 0⤊ 0⤋
x intercept is where y=0...
so 2/5x+1=0
2/5x=-1
x=-5/2...
2007-03-07 08:54:48 · answer #4 · answered by lUnJ@ 3 · 0⤊ 0⤋
let y=0 and voila!
2007-03-07 09:19:20 · answer #5 · answered by Allen F. 1 · 0⤊ 0⤋