2007-03-07 00:41:07 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Fluorine is the most electronegative element. That is, it has the strongest desire for electrons. It only needs one electron to complete an octet of electrons in its outer shell. When the shell is full with an octet, the atom is very stable. Therefore, needing only 1 electron is satisfactory for fluorine. It would become unstable if it were to grab another electron and have 1 unpaired electron in the next outer shell. Since it is very electronegative, it has no desire to lose an electron and wouldn't want to have 2 vacancies in it's shell. It is happy and stable with an oxidation number of 1.
2007-03-07 00:53:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Fluorine is a main group 7 element with 7 electrons in the valence shell. It needs just one electron to achieve the so-called octet (noble gas electronic configuration). Hence fluorine has a oxidation number of -1.
2007-03-07 01:53:36 · answer #2 · answered by myyahoo! 2 · 0⤊ 0⤋
Fluorine has 7 electrons in it truly is outermost shell. this suggests it needs a million more suitable electron to be reliable. Oxidation is income of electrons. because Fluorine needs to achieve one electron, it truly is oxidation state is -a million.
2016-12-05 08:58:33 · answer #3 · answered by ? 4 · 0⤊ 0⤋
fluorine only needs one electron to be happy
2007-03-07 01:49:46 · answer #4 · answered by xox_bass_player_xox 6 · 0⤊ 0⤋