Al reacts with excess copper II sulfate according to the reaction below. If 1.85g of Al react and the percent yeild of Cu is 56.6 what mass of Cu is produced?
2007-03-07 00:23:55 · 2 answers · asked by sweetangelbaby89_2004 1 in Science & Mathematics ➔ Chemistry
2 Al + 3 CuSO4 --> Al2(SO4)3 + 3 Cu
2 gram-atoms of Al yields 3 gram-atoms of Cu
1.85 grams / 26.98 g/mole = 0.0686 moles of Al
Moles of Cu formed:
0.0686 moles * (3/2) = 0.103 moles
0.103 moles * 0.566 = 0.0573 moles Cu
0.0573 moles * 63.55 g/mol = 3.64 g Cu
2007-03-07 01:56:10 · answer #1 · answered by Richard 7 · 9⤊ 0⤋
simply compare the number of Al atoms that are required to produce 1 atom of Cu, than multiply the weight of input Al by the ration of atomic weights of Cu/Al to get the weight of Cu produced
2007-03-07 08:30:50 · answer #2 · answered by Anonymous · 0⤊ 0⤋