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if we are given 2 charges Q and -Q,
equipotential lines are symmetrical above the mid-point between -Q and Q, anybody can explain it plz =]

2007-03-06 23:52:02 · 2 answers · asked by Tommy 1 in Science & Mathematics Physics

2 answers

Sure ... if you have two charges of opposite sign, they will create the same voltage at the same distance away from each with reversed signs of course. The equipotential for a plane will be a line which runs halfway between them; when you add the potentials there, you get zero. for a three dimensional system, it's a plane between them.

2007-03-07 00:17:00 · answer #1 · answered by Gene 7 · 0 0

Actually, they're co-axially symmetric around the line between Q and -Q.

HTH ☺

Doug

2007-03-07 00:15:23 · answer #2 · answered by doug_donaghue 7 · 0 0

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