im a first year student can any one help me?
2007-03-06 23:14:38 · 10 answers · asked by jezreel j 1 in Science & Mathematics ➔ Mathematics
5X-3X=8
2X=8
X=8/2
X=4
2007-03-06 23:21:52 · answer #1 · answered by cool mind 1 · 0⤊ 1⤋
5x-3x=8=>2x=8=>x=8/2=>x=4
2007-03-07 07:37:28 · answer #2 · answered by djin 2 · 0⤊ 0⤋
5x = 3x + 8 subtract 3x from both sifed
2x = 8 divide both sides by 2
x = 4 check by substitution
5*4 = 3*4 + 8 Yup, so we're done.
HTH âº
Doug
2007-03-07 07:20:53 · answer #3 · answered by doug_donaghue 7 · 0⤊ 1⤋
5x = 3x + 8
2x = 8 ( minus away the 3x)
x = 4 ( divide by two)
2007-03-07 08:47:36 · answer #4 · answered by Anonymous · 0⤊ 0⤋
5x=3x+8
5x - 3x = 8
2x = 8
x = 8: 2
x = 4
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2007-03-07 07:32:23 · answer #5 · answered by aeiou 7 · 0⤊ 0⤋
5x=3x+8
5x-3x=8
2x=8
x =4
2007-03-07 07:19:49 · answer #6 · answered by kwambonambi 3 · 0⤊ 1⤋
1) 5x - 3x = 8
2) 2x = 8
3) x = 4
Sorry...I typed it wrong just now.
2007-03-07 07:19:25 · answer #7 · answered by Anonymous · 0⤊ 1⤋
5x=3x+8
first.. 5x-3x. transposition i think.. there's no such thing!!
2x=8
both sides over 2
x=4
2007-03-07 07:20:12 · answer #8 · answered by Anonymous · 1⤊ 1⤋
just transpose all terms with the variable x on one side. then just do the equation. whether you add or subtract, multiply or divide. goodluck! more will come your way. and much more complicated than that one.
2007-03-07 07:46:06 · answer #9 · answered by swirlz 2 · 0⤊ 0⤋
What they said :)
2007-03-07 07:25:36 · answer #10 · answered by immaculately flawed 2 · 0⤊ 1⤋