is there anyway executing both if statement and else statement in c?

Answer 1

logically impossible, the moment the compiler executes the if statement it will skip the else statement

Answer 2

No you can't but if you use a swicth statement in C, C++ (NOT C.net and possibly C# as the functionality changed) you can e.g.

Switch (value) {
case 1:
doa();
case 2:
dob();
break;
default:
doc();
break;
}

Because the "case 1" does not contain a break statement it will fall through and execute the code in "case 2" so this is the same as

if (val == 1)
doa();
dob();
else if(val == 2)
dob();
else
doc();

Answer 3

In program logic, you are asking for a contradiction. If implies choice/s, else is when the choice/s do not satisfy the criteria for the, "IF".

To execute both the satisfied IF condition and the Unsatisfied, "ELSE" condition, "Example: If apple - do Pie, Else do Hot Rolls."

To satisfy your question; in the Do Pie, complete that Routine and then do the coding for Hot ROLLS.

Does that help!



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Answer 4

YOur question itself says not possible.
If else : is a branching statement which helps in executing either if part or else part.

i hope you are asking this question because someone showed you output wher both parts are executed!!

it is possible if you are creating thread and thread is running the else part main is running if part ( or vice-versa)

Or one tricky question

if()
printf("Good");
else
printf(" morning");


and expecting the output as Good Morning.
This is not exactly related to if statement, but the return value from printf function
You can do this by setting the somecondition into !printf("Good")

if(!printf("Good"))
printf("Good");
else
printf(" morning");


Hope it serve your need.
PC

Answer 5

Some time in a multi processing CPU, both cases get executed and the invalid one is discarded.

Answer 6

you won't be able to analyze 2 array-strings with "==" operator. attempt to apply "strcmp" function. int strcmp(const char* s1, const char* s2) the explanation it would not artwork is that the variable call of a character array in C/C++ is actual a pointer to 3 area of memory the place the array starts. So 2 "strings" should not be "equivalent" till they the two element to a similar memory area.