The vapor pressure of pure water at 110 degrees C is 1070 torr. A solution of ethylene glycol and water has a vapor pressure of 1.00 atm at 110 degrees C. Assuming that Raoult's law is obeyed, what is the mole fraction of ethylene glycol in the solution?
If you could give clear steps in your answer, as to HOW to did it, that would be great. I'm not looking for the answer- if you choose to check, it's .290, i'm looking for how to go about it. i know you use raoult's law, i just don't know where!
thank you!
2007-03-06 17:08:58 · 2 answers · asked by bree 3 in Science & Mathematics ➔ Chemistry
*how to do it
2007-03-06 17:09:26 · update #1
Raoult's Law in math form is:
Pi - Pf = XfPi or Xf = (Pi - Pf)/Pi
1.00 atm = 760 torr.
The change in pressure is 1070 torr - 760 torr = 310 torr.
The mole fraction = 310 torr/1070 torr = 0.2897 0r 0.290
See the sites below:
2007-03-06 18:25:22 · answer #1 · answered by Richard 7 · 10⤊ 0⤋
Q3) use (P - P' )/P = X the place P = 2.32 kPa P' = u would desire to discover this X = mole fraction of glucose in water = no. of moles of glucose / ( moles of glucose + water) moles of glucose = 10.8/a hundred and eighty.15 mass of water = quantity * density = one hundred ml * a million g/ mL = one hundred g so moles of water = one hundred/18 now discover X replace in formula, get d fee of P' ... 4) Use Charles' regulation PT = consistent so 136 kPa * 293 = 574 * P discover P thank you :)
2016-12-18 07:25:24 · answer #2 · answered by ? 4 · 0⤊ 0⤋