What is the molarity of a solution prepared by diluting 150. mL of 0.403 M HNO3 to 450. mL?

Question

What is the molarity of a solution prepared by diluting 150. mL of 0.403 M HNO3 to 450. mL

Answer 1

Simplistically 150 x 0.403 / 450 = 0.134 M

Answer 2

Molarity means the number of moles in 1000 ml of the solution.

1000 ml the original HNO3 acid solution contains 0.403 moles

Therefore 150 ml of it contains( 0.403 X .15 )moles = 0.06 moles.

Now this 0.06 moles are in 450 ml. How much moles canbe found in 1000 ml of this second HNO3 acid solution = (0.06 X 1000) / 450 = 0.1333 M

This is how I always do these type of calculations. I seldom use formulas, coz once you get used to formulas, you tend not to reason your answer.

Answer 3

150. mL of 0.403 M HNO3

multiply molarity by number of liters to get number of mol =.06045

molarity is moles / L right?

.06045 / .45 L = your answer