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I have a homework problem, and need help figuring out the answer. Show work if possible, please.

2007-03-06 15:51:55 · 2 answers · asked by efrosty 2 in Science & Mathematics Chemistry

Latent Heat of Fusion of Water: ∆Hfus(H2O)= 80 calories/ gram= 334 Joules/gram.

2007-03-06 17:29:55 · update #1

2 answers

(1.75 moles)(18 g/mole)(334 J/g)(1 kJ/1,000 J) =
10.521 kJ

2007-03-06 20:19:17 · answer #1 · answered by Helmut 7 · 0 0

Come on dog. If you had posted the latent heat of Ice for liquid to solid with your question, someone would have answered faster.

the latent heat of water from solid to liquid

Lsolid-liquid = 3.3 x 10/\5 J/kg 1.75 moles of water at 18 g / mol is about 31.5 g or .0315 kg

3.3 x 10/\5 J/kg * .0315 kg / 1000 = your answer

2007-03-06 17:08:54 · answer #2 · answered by whatwouldyodado2006 4 · 0 0

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