A transformer is designed to change 120 V into 10,000 V...?

3 ⤊

....and there are 5000 turns in the primary coil. How many turns are in the secondary coil? (Assume 100% efficiency.)

Any help would be awesome!

2007-03-06 15:18:34 · 3 answers · asked by Jade m 1 in Science & Mathematics ➔ Physics

For a 100% efficient transformer:
Voltage in/Voltage out = Turns in primary/turns in secondary
120/10000 = 5000/n
n=416667 turns

2007-03-06 15:56:19 · answer #1 · answered by Southpaw 5 · 2⤊ 0⤋

p=primary, s=secondary Assume 120 V on the Primary

Np/Ns=Vp/Vs

5000/x=120/10000 ==>x=10000/120*5000=416667 turns

2007-03-06 16:10:03 · answer #2 · answered by Rob M 4 · 0⤊ 1⤋

the ration of the primary turns to the secondary turns is the same as the ratio of the voltages,

10,000/120 = ?/5000

5000 x 10,000/120 = ?

2007-03-06 15:52:17 · answer #3 · answered by Anonymous · 1⤊ 1⤋