calculate the volume 3.00 moles of a gas will occupy at 24.0-degrees celsuis and 102.5kPa?
2007-03-06 14:50:48 · 5 answers · asked by goodies 1 in Science & Mathematics ➔ Chemistry
use the ideal gas law:
PV=nRT
and solve for Volume
V=nRT/P
convert temp to Kelvin: 24 degrees Celsius = 297.15 kelvin
use (8.314472 L · kPa · K-1 · mol-1) for R since pressure is in kPa
plug in the variables:
V= [(3)(8.314472 )(297.15)]/(102.5) = 72.3 L
2007-03-06 15:04:19 · answer #1 · answered by Anonymous · 1⤊ 0⤋
Well ideal gas law says PV=nRT, P= Pressure, V=Volume, n=number of moles, R= gas constant(8.3145 J/molK), T=Temperature in K.
K=273.15+ C, solve for V, V=(nRT)/(P)
Just plug and play buddy. Good luck!
2007-03-06 14:55:00 · answer #2 · answered by brian_holinsworth1 2 · 0⤊ 0⤋
PV=nRT
Solve for V.
This is simply the ideal gas law.
n is the amount of the gas you have: the moles of the gas you have.
Be sure that you convert properly. eg if you use R=8.31 L*kPa/mol*K
make sure that your T is in Kelvin, and your P is in kPa.
2007-03-06 14:59:22 · answer #3 · answered by Vicky 2 · 0⤊ 0⤋
PV=nRT
V=nRT/P
V=(3 moles) (8.3143 m3·Pa·K-1·mol-1) (297k)/(102.5 kPa)
V=72.274 m^3
2007-03-06 15:03:50 · answer #4 · answered by Matthew P 4 · 0⤊ 0⤋
http://en.wikipedia.org/wiki/Ideal_gas_law
just plug in to that formula. don't forget to fix your units (kPa -> 1000Pa, deg C -> K - 273, etc)
2007-03-06 14:59:10 · answer #5 · answered by shawntolidano 3 · 0⤊ 0⤋