2007-03-06 11:48:27 · 9 answers · asked by tamster 2 in Pets ➔ Other - Pets
If the dog is healthy and good enough to be shown, $400 is a bargain.
2007-03-06 11:52:24 · answer #1 · answered by Husker41 7 · 0⤊ 0⤋
A show whippet wanted for a pet? So it will not be shown anymore? Then $400 isn't too unreasonable depending on location. A show dog, intended for showing and later breeding would be very much more.
If your dog is being sold as a pet because it could not cut it in the show ring, then you'll want to have it spayed or neutered right away. Add that cost into the buying price for the dog.
2007-03-06 11:52:34 · answer #2 · answered by Robin D 4 · 2⤊ 0⤋
If you do this, spay or neuter him/her right away. Any whippet selling for that amount is NOT show quality. Could have a fabulous pedigree and show parents, but for $400 bucks? It'll never happen - unless they stole it and are selling a stolen dog. Spay or neuter and keep as a pet. End of discussion.
2007-03-06 12:08:00 · answer #3 · answered by amishpantry 3 · 0⤊ 1⤋
i think that is reasonable its actually a deal...but you need to ask one very impotant question first...why are they giving him up? write down all the questions you have so you can just ask them at one time...whippets are great...good luck with whatever you decide to do
2007-03-07 08:41:14 · answer #4 · answered by dotdotdot 5 · 0⤊ 0⤋
Depends on its pedigree and what the market for this breed at this age is in your area. Any bet could probably tell you, or a breeder.
2007-03-06 11:52:07 · answer #5 · answered by beez 7 · 0⤊ 0⤋
Uhhh, the last car we bought 2 years ago didn't even cost that, and we still drive it to work every day.
Guess it depends on your budget and priorities.
2007-03-06 11:51:17 · answer #6 · answered by Lisa 6 · 0⤊ 2⤋
What the hell is a whippet?
2007-03-06 12:14:26 · answer #7 · answered by ? 6 · 0⤊ 2⤋
Yes, if the dog has been vet-checked and okayed.
2007-03-06 11:50:56 · answer #8 · answered by Lisa E 6 · 1⤊ 0⤋
If it has it's papers. $400 is fair.
2007-03-06 11:52:08 · answer #9 · answered by Anonymous · 0⤊ 2⤋