help me plz lol physics homework im like so bad at it if u can plz also explain me?

Question

in 1992 maurizo domiliano walked 29752 m in 2.00h ,
a ) wats his average speed in m/s? ,
b ) supose he slows down to 3.00m/s at midpont of journey , but then picks up pace and accelerates to speed calculated in a . it takes 30.0 s to accelerate . find magnitude of average acceleration during this time interval

Answer 1

start by converting the 2 hours he took to seconds. 2*60*60=7200 seconds in 2 hrs

now you want m/s, so divide m by s

29752/7200~=4.13

now thats your answer to a. For b, find the amount he accelerated (delta velocity) by subtracting starting velocity from ending velocity

4.13-3=1.13

now you need that in meters per second per seconds, or m/s^2 so take the meters per second and divide by the number of seconds so you've got 1.13/30

Answer 2

First you have to convert hours into seconds. 120 min in two hours, times 60 seconds in a minute (7200 seconds) and divide that into 29752 meters to get part a.

I'm not sure about part b....sorry.