hi please help dynamics...have the answer need help doing it?

Question

a person is driving a 1500kg snowmobile down a hill. the hill is inclined at an angle of 30degrees to the horizontal and has a coeffcient of friction of 0.28. what force must the snowmobile's engine apply to cause the snowmobile to accelerate at 0.60g?
the answer is applied force= 5034 N

thanks!!!

Answer 1

A FBD of the snow mobile with positive forces down slope parallel to the snow
Gravity
m*g*sin(30)
Friction
=-m*g*0.28
Force of the motor
F

Sum of the forces = m*a
from above a=.60 g

m*g*sin(30)-
m*g*cos(30)*0.28+F
=m*g*.60

F=m*g*
(.60+cos(30)*.28-sin(30))

F=5034 N

j