2007-03-06 05:51:38 · 13 answers · asked by Julio L 1 in Computers & Internet ➔ Hardware ➔ Desktops
Intel Pentium Duo is like the "Smart Kid" in the class, while the Intel Celeron is like the "Special Needs Kid" who got left back twice...
2007-03-06 06:08:15 · answer #1 · answered by bpgveg14 5 · 0⤊ 0⤋
Intel Pentium 4
2007-03-09 19:33:01 · answer #2 · answered by galaxy_hunter91 4 · 0⤊ 0⤋
I am about 95% Sure that it would be Pentium over Celeron. But if you are buying a new computer I would go with the Intel Core Duo that was just released.
2007-03-06 05:56:33 · answer #3 · answered by BigDaddy 1 · 0⤊ 0⤋
This is simple,if the word CELERON is contained anywhere in the information about your computer,DO NOT BUY IT! For the small difference between Pentium or AMD processors don't waste your time on a Celeron processor.
2007-03-07 01:25:13 · answer #4 · answered by wayne548 3 · 0⤊ 0⤋
Intel pentium's are usually used on desktops, and Intel celeron's are usually made for Laptops to save battery life. But the Core 2 Duo's(two processors) are the best and the Quad processor's(four processors)(the best!!!)
2007-03-06 08:55:47 · answer #5 · answered by B-Rad 4 · 0⤊ 0⤋
Pentium.
In the beginning Celerons were tuned down Pentium processors. Generally Celeron processors perform remarkly worse when it comes to games and other applications that need a lot of cpu power.
2007-03-06 06:00:55 · answer #6 · answered by Martin I 3 · 0⤊ 0⤋
Intel Pentium, indeed.
2007-03-06 05:54:45 · answer #7 · answered by Anonymous · 0⤊ 0⤋
The Intel Core processors are the best, such as the Core Duo or Core 2 Duo.
2007-03-06 06:00:05 · answer #8 · answered by UbiquitousGeek 6 · 0⤊ 0⤋
celeron - is trimmed down pentium - so pentium is the better choice
(You may want to look at AMD as these are better still at arounnd a similar price)
2007-03-06 05:55:03 · answer #9 · answered by Anonymous · 0⤊ 0⤋
its always been pentium,
celeron handles basic computing and pentium handles more intense applications
2007-03-06 05:55:31 · answer #10 · answered by Anonymous · 0⤊ 0⤋