Hi please help, (dynamics) cant figure it out?? have the answer , just cant do it?

Question

a skateboarder slides down a frictionless ramp inclined at an angle 30degrees to the horizontal.he then slides across a frictionless horizontal floor and begins to slide up a second incline at an angle of 25degrees to the horizontal.the skateboarder starts at a distance of 10m from the bottom of the first incline.how far up the second incline will he go if the coefficient of kinetic friction on the second incline is 0.10?

the answer is 9.8 metres

thanks!!!!

Answer 1

use conservation of energy

the potential energy lost on the first ramp
sin(30)*m*g*10
the potential energy gained back on the second ramp
sin(25)*m*g*d

The energy lost to friction
N=cos(25)*m*g
F=cos(25)*m*g*.1*d

the energy must be conserved

sin(30)*10=
d*(sin(25)+cos(25)*.1)

d=sin(30)*10/
(sin(25)+cos(25)*.1)

d=9.74

j