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For example, soccer has 3 outcomes each match:

Team A wins
Team B wins
Draw (Tie)

theres a few things I want to know. 1, Lets say there are 8 matches. How many different combinations of outcomes can there be for all eight matches in total? I'm thinking 24 total outcomes but I have a feeling this isn't correct.

Also if you picked an outcome for each of the 8 matches what are the chances that you will correct?

Also please provide the formulas for coming to these conclusions. Thanks.

2007-03-06 01:24:33 · 5 answers · asked by Miqael K 2 in Science & Mathematics Mathematics

5 answers

See you already mentioned this in your question. There are 8 matches with 3 possible outcomes right?

So the number of possible outcomes is 3x3x3x3x3x3x3x3 or 3^8 times.


What's the probability that you will get the exact order of this? It's 1/3^8 since there's only one possible combination.

2007-03-06 01:57:35 · answer #1 · answered by spec1227 4 · 0 0

There are three outcomes. Here we have 8 matches each can result in 3 outcomes. So there are 3^8 combinations.
For example if there were two matches there are three outcomes for the macth 2 for each outcome in the match 1, that is 3*3. The same is true for 8 matches!

2007-03-06 10:44:49 · answer #2 · answered by mojtaba 1 · 0 0

8^3 = 512. there are 512 possible combinations of outcomes for the 8 matches.

the probability of getting an outcome correct is 1/3 since there are only 3 choices and you have to pick one.

2007-03-06 10:01:42 · answer #3 · answered by thesavageworm 3 · 0 0

You have 3 states for 8 elements so there are 3^8=6561 different outcomes. So you have 1 chance on 6561 to guess correctly.

2007-03-06 09:52:51 · answer #4 · answered by MadScientist 2 · 0 0

let's try it ok!
A vs B A wins looses or tied
ok this options can be on the 8 matches so you will work it out easily as you said
3[options you have]x8[number of matches]=18

2007-03-06 09:51:20 · answer #5 · answered by Anonymous · 0 0

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