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1: Write in interval notation: | x | ≥ 3
(-∞, ∞)
(-∞, -3] U [3, ∞)
[-3, 3]
No solution


2: Write in interval notation: | 2x | < 6
(-∞, ∞)
(-∞, -3) U (3, ∞)
(-3, 3)
No solution


3: Solve and write in interval notation: | x + 5 | ≤ 4
[-9, -1]
(-∞, -9] U [1, ∞)
(-∞, -1] U [1, ∞)
[-1, 1]


4: Solve and write in interval notation: | x | - 2 > 9
(-7, 11)
(-11, 11)
(-∞, -11) U (11, ∞)
(-∞, -7) U (11, ∞)

2007-03-06 01:17:48 · 4 answers · asked by me1026 1 in Science & Mathematics Mathematics

4 answers

1)
|x| > 3 can be rewritten as
x > 3 or x < -3
or
(-∞, -3] U [3, ∞)

2)
|2x| < 6
can be rewritten as
-6 < 2x < 6
-3 < x < 3
or
(-3, 3)

3)
| x + 5 | < 4
-4 < x + 5 < 4
-9 < x < -1
or
[-9, -1]

4)
| x | - 2 > 9
| x | > 11
x > 11 or x < -11
or
(-∞, -11) U (11, ∞)

2007-03-06 01:23:01 · answer #1 · answered by Mathematica 7 · 1 1

1: (-∞, -3] U [3, ∞)

2: (-3, 3)

3: [-9, -1]

4: (-∞, -7) U (11, ∞)
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2007-03-06 09:23:51 · answer #2 · answered by aeiou 7 · 0 1

1. [-3,3]

2. (-3,3)

3. [-9,-1]

4. x > + - 11 and (-11,11)

2007-03-06 09:30:14 · answer #3 · answered by physicist 4 · 0 0

1)ans is the 2nd option
2)ans. is the 3rd option
3)ans. is the 1st option
4)ans. is the 3rd option

2007-03-06 09:25:47 · answer #4 · answered by SS 2 · 0 1

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