A rock is thrown straight upward from the edge of a 30 meter cliff, rising 10 meters then falling all the way down to the base of the cliff, find the rocks displacement.
2007-03-06 01:01:40 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
The rock travelled a total of 50 meters. I don't know the initial upward speed but I know the deceleration (-9.8m/s^2). So it took about a second to reach its maximal height before it started falling. It then travelled 40 meters down into the bottom of the cliff. At 9.8 m/s^2, it took a little over 2 sec to reach the bottom of the cliff. Therefore the total time it took is slightly more than 3 secs.
2007-03-06 01:30:30 · answer #1 · answered by misoma5 7 · 0⤊ 0⤋
i think its -30m if u consider upward +ve. bcoz accordin to u its going 10m up(+ve) and then ofcourse 10m+30m down(-ve), so 10-40=-30m. we cant use any other equation as we dont have any information. i hope its ok.
2007-03-06 09:58:00 · answer #2 · answered by Anindita Roy 1 · 0⤊ 0⤋