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4 answers

Yes. d(x^3)/dx, by the power rule, is 3x^2. Then you plug in your point--3 * (0^2) = 0. So the slope of your tangent line is zero.

2007-03-05 20:00:17 · answer #1 · answered by Anonymous · 0 0

Yes. The tangent is the x-axis. If y = x^3, then y' = 3x^2, which is 0 at (0, 0).

2007-03-06 04:11:14 · answer #2 · answered by Anonymous · 0 0

Yes.
f(x) = x³
f'(x) = 3x²

f'(0) = 0

The tangent is the x axis. If you look closely at the origin, you will see that x³ is flat as you get very close to the origin.

2007-03-06 04:02:39 · answer #3 · answered by novangelis 7 · 0 0

f(x)=x^3
f'(x)=3x^2 so if x=0 then the rate of change is also 0. That means that the tangent line of the function curve is parallel to(and actually lies on) the x-axis at that point.

2007-03-06 04:00:17 · answer #4 · answered by Sergio__ 7 · 0 0

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