Yes. d(x^3)/dx, by the power rule, is 3x^2. Then you plug in your point--3 * (0^2) = 0. So the slope of your tangent line is zero.
2007-03-05 20:00:17
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answer #1
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answered by Anonymous
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Yes. The tangent is the x-axis. If y = x^3, then y' = 3x^2, which is 0 at (0, 0).
2007-03-06 04:11:14
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answer #2
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answered by Anonymous
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Yes.
f(x) = x³
f'(x) = 3x²
f'(0) = 0
The tangent is the x axis. If you look closely at the origin, you will see that x³ is flat as you get very close to the origin.
2007-03-06 04:02:39
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answer #3
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answered by novangelis 7
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f(x)=x^3
f'(x)=3x^2 so if x=0 then the rate of change is also 0. That means that the tangent line of the function curve is parallel to(and actually lies on) the x-axis at that point.
2007-03-06 04:00:17
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answer #4
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answered by Sergio__ 7
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