vector A has a magnitude of 188units and points at an angle 30 north west.vector B points an angle of 50 north east.vector C points at an angle of 20 south west.the 3 vectors add to give a resultant vector that is zero.using components ,find the magnitudes of vectors B and C
2007-03-05 19:29:19 · 2 answers · asked by trick*star 1 in Science & Mathematics ➔ Physics
188cos30 + Bcos50 = Ccos20
188sin30 + Csin20 = Bsin50
Bcos50 - Ccos20 = - 188cos30
Bsin50 - Csin20 = 188sin30
-Bsin50cos50 + Csin50cos20 = 188sin50cos30
Bsin50cos50 - Ccos50sin20 = 188cos50sin30
C(sin50cos20 - Ccos50sin20) = 188(sin50cos30 + cos50sin30)
C = 188(sin50cos30 + cos50sin30)/(sin50cos20 - Ccos50sin20)
C = 370.28771513259023032189537724566
C ≈ 370.2877
188sin30 + Csin20 = Bsin50
B = 288.03271061273574123609963660884
B ≈ 288.0327
check:
188cos30 + Bcos50 = Ccos20
347.95663347776958075252764472438 =?347.95663347776958075252764472433
2007-03-05 20:20:32 · answer #1 · answered by Helmut 7 · 0⤊ 0⤋
Helmut, it's ridiculous to include that many digits in your answer! The data was only given to two or three places, so that's all that counts in the answer. Sheesh!
2007-03-05 21:12:24 · answer #2 · answered by hznfrst 6 · 0⤊ 0⤋