plz can u solve it
2007-03-05 17:57:10 · 2 answers · asked by **vinny** 2 in Science & Mathematics ➔ Physics
a lot
2007-03-05 17:59:42 · answer #1 · answered by achronicfan 3 · 0⤊ 0⤋
yes, here is the solution,
first calculate energy by a photon:-
that is hc/WL which is [(6.626*10^-34)*(3*10^8)]/(5893*10^-10)
so,
E= 3.37*10^-19 Joule
that is the energy of one photon
now energy of n photon is n*E
where n is n photons per sec
and here 100w means 100J per sec.
therfore,
equating nE with 100 gives n as,
n = 100/E
n = 100/(3.37*10^-19)
n= 29.67 * 10^19
n = 2.9 * 10^20
but photon can't be in fraction so taking integer which is just greater to fraction(we can't take less because then we are not able to get required energy)
so,
n = 3*10^20
that's it.
bye........
2007-03-10 00:28:50 · answer #2 · answered by Tarun J 2 · 0⤊ 0⤋