write a program that will print out the numbers from 53 to 48, backwards,all on one line.Print Starting & Done

Question

The full question:
Using a while loop, write a program that will print out the numbers from 53 to 48, backwards, all on one line. Print the messages "Starting" and "Done" before and after the line of numbers.

Sample output :
Starting
53 52 51 50 49 48
Done

In C++ code

Answer 1

ummm, pretty simple to do. did you at least TRY to write it?

main()
{
int number = 53;
char ch[10];
cout<<"Starting"< while (number > 47)
{
itoa(number, ch, 10);
cout< number--;
}
cout< }

Answer 2

# written in Python
print "Starting"
for i in range(53, 47, -1): print i,
print
print "Done"

# damn, that was easy.

Answer 3

in PHP

echo "Starting ";
for ($i = 53; $i <= 48; $i--) echo $i . " ";
echo "Done";
?>

Answer 4

int a=54;


for( int b=a; b>48; b--)
{
cout< }