The equation I have doesn't seem to fit???
? Delta Tbp=Kbp(m)??? is this the equation I would use?
what is the boiling point of a solution containing 4.66 g of caffeine
C8 H10 N4 O2 dissolved in 15.0 g of benzene?
The boiling point of pure benzene is 80.1 degrees C. The boiling point elevation constant Kb = 2.53 degrees C/molal
2007-03-05 14:52:03 · 3 answers · asked by ~~Shelly~~ 2 in Science & Mathematics ➔ Chemistry
Yes it is the correct equation
ΔTb= Kb*m
As I explained in my answer to your other question
m= 1000*g/(MW*G)
Where g is the mass of solute in grams
MW the molecular weight of solute
G the mass of solvent in grams
If Tbo is the boiling point of pure solvent and Tb that of the solution, the the elevation is
ΔTb= Tb-Tbo = Kb*m =1 000*Kb*g/(MW*G) =>
Tb=Tbo + 1000*Kb*g/(MW*G)=
=80.1+ 1000*2.53*4.66/(194*15) = 84.2 deg C
2007-03-05 21:32:47 · answer #1 · answered by bellerophon 6 · 1⤊ 0⤋
Water has a higher freezing element and a melting element because of the very solid charm between water molecules, giving upward push to the formation of hydrogen bonds. although this is fantastic to discover that RMM (relative molecular mass) of similar different compounds like water, which has H2O=18 when compared with Methane (RMM=16), Ammonia (RMM=17) are ALL gases at 0 ranges except water, it truly is at this is reliable state. the reason being as above, besides, it has a intense latent warmth of vaporization, requiring a great deal of power to over some the forces of charm between the molecules, allowing them to replace from reliable to liquid, and liquid to gas. wish this helps!
2016-11-28 01:22:27 · answer #2 · answered by Erika 4 · 0⤊ 0⤋
the boiling point to the solution would be 46.2 so this throws your therory right out the window the point at which binzene evaporates is not 80.1 it is 76.4 so the equation has no answer except in the third power of 12 which would be a mathematical hypothanuse and it cant be solved hopothectically.
2007-03-05 15:03:14 · answer #3 · answered by Anonymous · 0⤊ 1⤋