A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular v

Question

A gymnast is performing a floor routine. In a tumbling run she spins through the air, increasing her angular velocity from 3.00 to 4.45 rev/s while rotating through one-half of a revolution. How much time does this maneuver take?

Answer 1

angle = change in angular velocity times time

Theta= dw t
Theta - angle of revolution
dw - change in angular velocity
t - time

1 rev = 2 pi
in this case theta= pi (half of a revolution)

t=theta / dw
t= pi/(2 pi (4.45 - 3.0)
t= 1/(2(4.45 - 3.0)) = 0.345 sec

Answer 2

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