the cylinder and pulley turn without friction about stationary horizontal axles that pass through their centers. A light rope is wrapped around the cylinder, passes over the pulley, and has a 3.00-kg box suspended from its free end. There is no slipping between the rope and the pulley surface. The uniform cylinder has mass 5.00 kg and radius 40.0 cm. The pulley is a uniform disk with mass 2.00 kg and radius 20.0 cm. The box is released from rest and descends as the rope unwraps from the cylinder.
Find the speed of the box when it has fallen 1.50
2007-03-05 14:07:30 · 1 answers · asked by missincredible 1 in Science & Mathematics ➔ Physics
First figure out the force acting on the box (3 Kg X 9.8 M/s^2)
Then realize that the speed of the box will be the same as the rotational speed of the cylinder after 1.5 Meters of rope has moved across it...
The circumference of the cylinder is also useful here... 2 X pi X .4 Meters...
And since the pulley has to rotate as well, C = 2 X pi X .2 Meters
Use your equation for torque (rotational force) to see how fast the cylinder is turning after 1.5 Meters of rope have moved through.... This is a tough one, but if you stick with it I'm sure you'll get the answer. Draw a picture (force diagram) so you can 'see' it better.
2007-03-05 14:22:11 · answer #1 · answered by eggman 7 · 0⤊ 0⤋